two trains startfrom station A and B and travel toeardseach at other at speed of 50 km per hour and 60 km per hour restively. at the timeof their meeting, the second train has travelled 120 km more than the first the distance between A and B is.
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Suppose if they meet after x hours
Then 60x-50x=120
10x=120 = x=20 hour
Distance travel =60×12+50×12=720+600=1320 ans
Then 60x-50x=120
10x=120 = x=20 hour
Distance travel =60×12+50×12=720+600=1320 ans
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