two trains take 3sec to pass one another when going in the opposite direction but only 2.5sec if the speed of one of one is increased by 50%.the time one would take to pass the other when going in the same direction at their original speed is?
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Answer:
15 SEC
Explanation:
t= d/x+y =3
when speed of one is increased by 50%:t=d/1.5x+y =2.5
3x+3y=3.75x+2.5y
0.5y+0.75x
y=1.5x
d=3(x+y)=3(2.5x)=7.5x
thus, time for train moving in same direction= d/y-x=7.5x/1.5x-x=7.5/0.5=15 sec
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