Question

two triangular pieces ABC and BCD of paper are joined together form a big triangle ABD as shown in the adjoining figure. Find the area of triangle ABD

Answer 1

${\bold{\mathcal {\blue {\boxed {hii\:friend}}}}}$


here is YOUR ANSWER :-



It is better to use normal formula instead of hero's formula (of you're in 9th).



$let's solve it:-$

We have, height =5.5 cm
base =10+8 =18 cm

hence let's use the formula


$1 \div 2(bh)$


$= 1 \div 2(18 \times 5.5)$




$= 1 \div 2(99)$




$= 49.5 \: \: \: cm {}^{2}$






HOPE IT HELPS...



#nks23❤

Answer 2

Answer:

Step-by-step explanation:

Base of ∆ABD = 10+8 = 18cm

Altitude of ∆ABD = 5.5cm

Area of ∆ABD = 1/2 * 18 * 5.5 = 49.5 cm²