Question

Two tuning forks have the frequencies 512Hz and 516Hz .No of beats produced by these forks per second will be??

Answer 1

Answer:

4 beats

Explanation:

No.of beats = v2-v1

= 516-512

= 4

Answer 2

Answer:

Number of beats produced by these forks per second will be=4.

Explanation:

Given:

First frequency f₁=512Hz

Second frequency f₂=516Hz

Formula use:

Number of beats produced by the forks per second=Second frequency f₂-First frequency f₁

Time period=$\frac{1}{f}$

Solution:

Number of beats produced by the forks per second= f₂-f₁

                                                                                      =516Hz-512Hz

                                                                                      =4Hz

Therefore, number of beats produced by the forks per second is 4Hz.

Beat frequency=4Hz

Time period=$\frac{1}{f}$

Time period=$\frac{1}{4}$S=0.25S

Tuning forks:

• An acoustic resonator in the shape of a two-pronged fork, with the tines made of a U-shaped bar of elastic metal, is a tuning fork (usually steel).
• When struck on a surface or with an object to send it vibrating, it reverberates at a precise fixed pitch and emits a clean musical tone once the high overtones have subsided.

• The two prongs' length and bulk affect the tuning fork's pitch.
• They are dependable sources of pitch that is typically used to tune musical instruments.

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