Math, asked by mailtoadvaithajith, 1 year ago

Two vertices of an isosceles triangle are (2,8) and (10,2)find the third vertex if length of equal sidesw is 10 units

Answers

Answered by himanish912
3

Answer:

Step-by-step explanation:

let the third vertex is A(x,y)

and the given vertex are of base of isosceles Triangle B(2,8) and C(10,2)

As we know that two sides of isosceles Triangle are equal

Thus we calculate AB and AC by distance formula

AB=AC

put this value in

by this way we can solve the value of y by solving Quadratic equation.

thus value of x


himanish912: let the third vertex is A(x,y)
and the given vertex are of base of isosceles Triangle B(2,8) and C(10,2)

As we know that two sides of isosceles Triangle are equal

Thus we calculate AB and AC by distance formula

AB=AC

put this value in

by this way we can solve the value of y by solving Quadratic equation.
thus value of x

Read more on Brainly.in - https://brainly.in/question/6792015#readmore
Answered by himanish912
0

Answer:

Step-by-step explanation:

let the third vertex is A(x,y)

and the given vertex are of base of isosceles Triangle B(2,8) and C(10,2)

As we know that two sides of isosceles Triangle are equal

Thus we calculate AB and AC by distance formula

AB=AC

put this value in

by this way we can solve the value of y by solving Quadratic equation.

thus value of x

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