Two vertices of an isosceles triangle are (2,8) and (10,2)find the third vertex if length of equal sidesw is 10 units
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3
Answer:
Step-by-step explanation:
let the third vertex is A(x,y)
and the given vertex are of base of isosceles Triangle B(2,8) and C(10,2)
As we know that two sides of isosceles Triangle are equal
Thus we calculate AB and AC by distance formula
AB=AC
put this value in
by this way we can solve the value of y by solving Quadratic equation.
thus value of x
Answered by
0
Answer:
Step-by-step explanation:
let the third vertex is A(x,y)
and the given vertex are of base of isosceles Triangle B(2,8) and C(10,2)
As we know that two sides of isosceles Triangle are equal
Thus we calculate AB and AC by distance formula
AB=AC
put this value in
by this way we can solve the value of y by solving Quadratic equation.
thus value of x
Similar questions
and the given vertex are of base of isosceles Triangle B(2,8) and C(10,2)
As we know that two sides of isosceles Triangle are equal
Thus we calculate AB and AC by distance formula
AB=AC
put this value in
by this way we can solve the value of y by solving Quadratic equation.
thus value of x
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