Question

Two waves represented by y1= 3sin 200x-150t and y2 = 3cos 200x- 150t are superposed where x and y are in metrw and t us in second calculats the amplitude of resultant wave

Answer 1

Hey dear,

◆ Answer-

3 m
.

◆ Explaination-

Let 200x-150t = θ,

Then,

y1 = 3 sinθ

y2 = 3 cosθ
.

Magnitude of resultant displacement is given by -

y = √(y1^2 + y2^2)

y = √[(3sinθ)^2 + (3cosθ)^2]

y = 3 √[(sinθ)^2 + (cosθ)^2]

y = 3 m

Amplitude of resultant wave is 3 m.

Hope this helps you...