Question

Two wires A and B are vibrating with the same fundamental frequency.Following quantities associated with wire A & B are changed. change in which one of these quantities will not produce beats between A and B * stretching force Distance of the wire Amplitude of vibrations Material of the wire​

Answer 1

amplitude of the vibrations

v=λ×f

v=

μ

T

f ∝

T

and also T would depend on diameter of the wire

f ∝

μ

1

∴ amplitude of vibrations will not affect the frequency

⇒ change in amplitude of vibrations will not produce the beat

Answer 2

Explanation:

We know that the speed of a wave is given by the formula:

$v=\nu*\lambda$  ----(1)

where, $v$ denotes velocity,

$\nu$ denotes frequency,

$\lambda$ denotes the wavelength.

also, speed of a wave in a string is given by the formula:

$v=\sqrt{\frac{T}{\mu} }$ ----(2)

where, $T$ is the tension in the string,

and $\mu$ is the mass per unit length of the string.

from equation (1) and (2) we can say that,

$f\propto \sqrt{T}$

and also tension $T$ would depend on the diameter of the wire

Also, $f\propto \frac{1}{\sqrt{\mu} }$

From the above two results, we can see that frequency does not depend on the amplitude of the wave.

​∴ the amplitude of vibrations won't affect the frequency

Hence, we can say that changing amplitude will not produce the beat.

#SPJ2