Two wires of same length (and of different material) are tied with two equal mass to hang. The
diameter of the wires are 1 mm and 2 mm. If the expansion in length of the first wire is 3 times of the
second, compare the young's modulli of the two wires.
Answers
Answered by
3
l1= L/2. d1=2d
l2=L. d2=d
Y and F is same for both the wires:
increase in length=
FL/AY
1st wire:
increase in length=
F(L/2)/(π2d)²Y
4FL/8πd²Y
FL/2πd²Y
2nd wire : increase in length.
FL/πd²Y
Ratio:
FL/2πd²Y: FL/πd²y
= 1:2
Answered by
3
Answer:
Answer is 4:3
This is the correct answer
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