Question

two wires of same metal have the same area of cross section but their lengths in ratio 3:1. what should be the ratio of current flowing through them respectively. when the same potential difference is supplied across each of their length​

Answer 1

Answer:

Ratio of cross-sectional areas of the wires = 3 : 1 and resistance of thick wire (R1) = 10 Ω. = R1 + R2 = 30+ 10 = 40 Ω.