Question

Two zeroes of cubic polynomial ax³ + 3x² - bx - 6 are -1 and -2. Find the other zeroes also. ​

Answer 1

Answer:

=> a = 2 put in --(1)

b-3=2

=> b = 5 now put this value in Equation

ax³ + 3x²-bx - 6 = 0

=> 2x³ + 3x² -5x - 6 = 0

two zeroes are given (-1, -2)

(x + 1)(x + 2) = x² + 2x + x + 2 = 0

=> x² + 3x + 2 =0

x² + 3x + 2)2x³ + 3x² - 5x - 6(2x - 3 2x³ + 6x² + 4x

-3x² - 9x - 6 -3x² - 9x - 6 + + +

hence another zeroes is

2x - 30

=> x = 3/2

Step-by-step explanation:

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