Two zeroes of cubic polynomial ax³ + 3x² - bx - 6 are -1 and -2. Find the other zeroes also.
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Answer:
=> a = 2 put in --(1)
b-3=2
=> b = 5 now put this value in Equation
ax³ + 3x²-bx - 6 = 0
=> 2x³ + 3x² -5x - 6 = 0
two zeroes are given (-1, -2)
(x + 1)(x + 2) = x² + 2x + x + 2 = 0
=> x² + 3x + 2 =0
x² + 3x + 2)2x³ + 3x² - 5x - 6(2x - 3 2x³ + 6x² + 4x
-3x² - 9x - 6 -3x² - 9x - 6 + + +
hence another zeroes is
2x - 30
=> x = 3/2
Step-by-step explanation:
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