Twoequal sides of a triangle areeach 5meters less than twice the third side.if the perimeter of the triangle is 55meters. Find the lengths of its sides
Answers
Answered by
6
let the third side be x..
equal sides = 2x - 5
so accordind to question..
perimeter of triangle = 55
x + 2x - 5 + 2x - 5 = 55
5x - 10 = 55
5x = 55 + 10
5x = 65
x = 65÷5 =13
length of sides
2x-5 = 2×13 -5 = 21
" " " " " " " " " " " = 21
third side = 13 .....ans
equal sides = 2x - 5
so accordind to question..
perimeter of triangle = 55
x + 2x - 5 + 2x - 5 = 55
5x - 10 = 55
5x = 55 + 10
5x = 65
x = 65÷5 =13
length of sides
2x-5 = 2×13 -5 = 21
" " " " " " " " " " " = 21
third side = 13 .....ans
Answered by
2
let the third side be x and two sides x-5 each so
A.T.Q x+x-5+x-5=55
3x-10=55
3x=45
x=15
A.T.Q x+x-5+x-5=55
3x-10=55
3x=45
x=15
Similar questions