Question

U
0.1 IVI UTULUSE
253) In 1 molal aqueous C2H5OH solution, the mole
fraction of C2H5OH is:
(a) 0.1
(b) 0.9
(c) 0.0177
(d) 1.0​

Answer 1

Answer:

Mole fraction of C2H5OH = Moles of ethanol / moles of ethanol + moles of water

                                          = 5 / 5+55.5

                                          = 5/60.5

                                          = 0.08

And thus mole fraction of water = 1- 0.08

                                                  = 0.9

b)0.9