Question

u want the ans in detailed form

Answer 1

hey here is you answer
===========================
${x}^{2} + x - 2 \\ {x}^{2} + 2x - x - 2 \\ x(x + 2) - 1(x + 2) \\ (x - 1)(x + 2) \\ x = 1 \: or \: - 2 \\ \alpha = 1 \\ \beta = - 2$
relation between zeros :
$\alpha + \beta = - \frac{b}{a} = \frac{ - 1}{1}$
$\alpha \beta = \frac{c}{a} = \frac{ - 2}{1}$
given :
$= \frac{1}{ \alpha } - \frac{1}{ \beta } \\ = \frac{ \beta - \alpha }{ \alpha \beta } \\ = \frac{ - 2 - 1}{ - 2 \times 1} \\ = \frac{ - 3}{ - 2} \\ = \frac{3}{2}$
================================
hope it may helpful to you
plzz mark me as brainlist