Question

U235 by92 experiences one alpha decay and one beta decay find the number of neutrons in the final daughter nucleus that is formed

Answer 1

Answer:

in alpha decay, the mass number decreases by 4 while the atomic number increases by 2. while in beta decay, the atomic number decreases by 1 while the mass number remains constant.

so the mass number(A) of U after alpha decay =235-4=231

and atomic number(Z)=92-2=90

and after beta decay,

mass number(A)=231

atomic number(Z)=90+1=91

so, the final daughter nucleus is a nucleus with

A-Z=231-91=40 neutrons and 91 protons

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