Question

Uniform acceleration of 4 m/s how much distance will it cover 10 s after it starts moving from rest

Answer 1

s= ut+1/2at^2

s= distance

u=0(from rest)

t=10...a=4

s=1/2×4×10×10

s=200m

hope it helps

Answer 2

By using the second formula of kinematics
x = u*t+1/2*a*t^2
Where x is displacement
u is initial velocity
a is acceleration
t is time

Therefore,

x = (0)*(10) + 1/2*(4)*(10)^2 = 200 metres

Therefore, the distance covered will be 200 metre