Uniform acceleration of 4 m/s how much distance will it cover 10 s after it starts moving from rest
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Answered by
1
s= ut+1/2at^2
s= distance
u=0(from rest)
t=10...a=4
s=1/2×4×10×10
s=200m
hope it helps
s= distance
u=0(from rest)
t=10...a=4
s=1/2×4×10×10
s=200m
hope it helps
vipulghorpade1112200:
thanks
Answered by
1
By using the second formula of kinematics
x = u*t+1/2*a*t^2
Where x is displacement
u is initial velocity
a is acceleration
t is time
Therefore,
x = (0)*(10) + 1/2*(4)*(10)^2 = 200 metres
Therefore, the distance covered will be 200 metre
x = u*t+1/2*a*t^2
Where x is displacement
u is initial velocity
a is acceleration
t is time
Therefore,
x = (0)*(10) + 1/2*(4)*(10)^2 = 200 metres
Therefore, the distance covered will be 200 metre
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