units digit of a 2-digit number is two-third of its tens digit.If the sum of the units and tens digit is 96,find the number.
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let x be the unit digit and y the tens digit then,
x = (2/3)y
6 = (2/3)y
y =( 6/3)/2 = 9
The number = 96 ( unit digit - 6 , tens digit - 9)
x = (2/3)y
6 = (2/3)y
y =( 6/3)/2 = 9
The number = 96 ( unit digit - 6 , tens digit - 9)
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