Question

Unpolarized light of intensity j is incident on a system of fwo polarizes. A folowed by

b. The intensity of eme

Answer 1

As we have learned

Malus Law -

I= I_{0}\cdot \cos ^{2}\theta

\theta = angle made by E vector with transmission axis.

- wherein

I= Intensity of transmitted light after polarisation .

I_{0}= Intensity of incident light.

both A and B should have same orientation of transmission axis only then we will have intentisity of I/2

let c makes angle \Theta with A then I/2\cos ^{2}\Theta \cdot \cos ^{2}\Theta = I/3

or

\cos \Theta = (2/3)^{1/4}

Option 1)

\cos \Theta = \left ( \frac{2}{3} \right )^{1/2}

This is incorrect

Option 2)

This is correct

Option 3)

\cos \Theta = \left ( \frac{1}{3} \right )^{1/2}

This is incorrect

Option 4)

\cos \Theta = \left ( \frac{1}{3} \right )^{1/4}

This is incorrect