Upon hydrolysis compound X in the presence of NaOH we get C2H5OH and CH3CoOO^_Na^+ ,the compound X is :-
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ch3cooc2h5....
Naoh in the presence of H + would give Na+ leaving behind water .
Na+ attack ch3coo c2h5
as it's ch3coo - and c2h5+
so it will attack ch3coo-
giving ch3coona
and then oh - from water attack c2h5 + giving c2h5oh
Naoh in the presence of H + would give Na+ leaving behind water .
Na+ attack ch3coo c2h5
as it's ch3coo - and c2h5+
so it will attack ch3coo-
giving ch3coona
and then oh - from water attack c2h5 + giving c2h5oh
Anonymous:
give whole reaction and process
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