Question

URGENT..............

Answer 1

let the capacitance of all capacitors be 'C' ..
equivalent capacitance when connected in series = (1/C)+(1/C)+(1/C)+(1/C)+(1/C) = 1/4 (given)
=> 5/C = 1/4
=> C = 5x4 = 20uF
Now, equivalent capacitance when connected in parallel = C+C+C+C+C = 5xC = 5x20 = 100uF = 100 x 10^(-6) F = 10^(-4) F ...
Energy stored = E = (1/2)CV^2 = (1/2)x10^(-4)x(400)^2 (given:- V=400V)
=> E = (1/2) x 10^(-4) x (16x10^4) = (1/2)x16
=> E = 8 J ....

Answer 2

Answer:

Explanation:Acceleration = (Final velocity - Initial velocity )/ Time

Acceleration = (0 - 50) /  5

Acceleration = -50 / 5

Acceleration = -10m/s^2

Hope this answer is correct..........

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