Chemistry, asked by yagikajay007, 5 months ago

Use standard enthalpies of formation, calculate the value of ∆rH0 for the reaction 2H2S + 3O2 → 2H2O +2SO2
∆fH0 [H2O]= -285.5 kj/mol
∆fH0 [H2S]= -21.17 kj/mol
∆fH0 [SO2]= -296.86 kj/mol ​

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Answered by sikhi
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hope it helps...........

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