Question

Usha swims in 90 metre long swimming pool she covers 180 m in 1 minute by swimming from one end to another and back along the same straight find the average speed and velocity of usha

Answer 1

AVG speed=total distance/total time
=180m/60 sec
=3 m/s
AVG velocity=displacement/total time
=0/60sec
=0 m/s

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Answer 2

Answer:

Average speed = 3 ms⁻¹

Average velocity = 0 ms⁻¹

Explanation:

Total distance covered by usha in 1 minute = 180 metres

Displacement of Usha in 1 minute = 0 metres

Average speed = Total distance covered / total time taken

= 180/1 min

1 min = 60 seconds

180/60 = 3 m s⁻¹

Average velocity = Displacement / time taken

0/60 seconds

= 0ms⁻¹

The average speed of Usha is 3 ms⁻¹ and average velocity is 0 ms⁻¹