Math, asked by nihaldiv666, 1 year ago

Using a suitable identity expand (x³-y³)(x³+y³)

Answers

Answered by ItzRadhika
7

Answer:

(x³-y³) = (x-y) (x²+xy+y²)

(x³+y³) = (x+y) ( x²- xy+y²)

Answered by dilanshimohak
0

(x²-y®) =) (x-y) (x²+xy+y²).

(x²+y®) =» (x+y) ( x²- xy+y?)

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