Using a suitable identity expand (x³-y³)(x³+y³)
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Answer:
(x³-y³) =》 (x-y) (x²+xy+y²)
(x³+y³) =》 (x+y) ( x²- xy+y²)
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(x²-y®) =) (x-y) (x²+xy+y²).
(x²+y®) =» (x+y) ( x²- xy+y?)
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