Question

using binomial theorem expand x+3^5 if ar, ar^2,......,ar^n-1 .(r+1) is a GP then Sn=ar+ar^2......+ar^n-1 ​

Answer 1

$(x + 3) {}^{5} \\ = 1{x}^{5} + 5x {}^{4} \times 3 {}^{1} + 10 {x}^{3} \times {3}^{2} + 10 {x}^{2} \times {3}^{3} + 5x \times {3}^{4} + {3}^{5} \\ = {x}^{5} + 15 {x}^{4} + 90 {x}^{3} + 270 {x}^{2} + 405x + 243$

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Answer 2

Answer:

(x+3)

5

=1x

5

+5x

4

×3

1

+10x

3

×3

2

+10x

2

×3

3

+5x×3

4

+3

5

=x

5

+15x

4

+90x

3

+270x

2

+405x+243

hope

it

will

help

u

mark as brainliest