Using differential find approximate value of (0.999)^1/10.
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0.999
⇒![\sqrt[10]{0.999}=0.0999](https://tex.z-dn.net/?f=++%5Csqrt%5B10%5D%7B0.999%7D%3D0.0999+ "\sqrt[10]{0.999}=0.0999")
Ans:0.0999
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⇒
Ans:0.0999
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