Using euclid's algorithm to find the HCF of 2184 , 273 and 3360.
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Answer:
HCF = ( 273 , 2184 , 3360 ) = 21
Step-by-step explanation:
2184 = 273 × 8 + 0
⇒ HCF( 273 , 2184 ) = 273
Now the HCF ( 273 , 3360 ) :
3360 = 273 × 12 + 84
273 = 84 × 3 + 21
84 = 21 × 4 + 0
∴HCF ( 273 , 2184 , 3360 ) = 21
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