Math, asked by seksha27, 10 months ago

Using factorisation find the roots of the quadratic equation 6z^2-5z-21=0

Answers

Answered by dhareaveer
2

Answer:

6z2 - 5z - 21 = 0.  

6z2 - 14z + 9z - 21 = 0

2z(3z - 7) +3 (3z - 7)

(2z + 3) (3z - 7) = 0

(2z + 3) = 0 or (3z - 7) = 0

z = -3/2 or z = 7/3    

Answered by Anonymous
12

 \huge \mathfrak \red{answer}

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 \huge \sf  \underline{Question}

⟹ Using factorisation find the roots of the quadratic equation 6z^2-5z-21=0

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step by step explanation:

 \tt \red{6 {z}^{2} - 5z - 21 = 0}

 \tt \blue{⟹6 {z}^{2} - 14z + 9z - 21 = 0}

 \tt \green{⟹ 2z(3z - 7) + 3(3z - 7)}

 \tt \orange{⟹ \: (2z + 3)(3z - 7) = 0}

 \sf \pink{⟹ \: (2z + 3) = 0}

or

 \tt \pink{⟹ \: (3z - 7 )= 0}

then

 \bf  \huge\red{ z \:  =  \frac{ - 3}{2}}

or

 \bf \huge \red{z =  \frac{7}{3}}

I hope it's help u

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