Question

Using formula calculate the amount and C.I. on rs 30000 for 2 years at 8 percent p.a. compounded annually​

Answer 1

Answer:

C.I = 4992.

Amount = 34992

Step-by-step explanation:

As per the information provided in the question, We have :

• Principal = 30000
• Time = 2 years
• Rate = 8%

We are asked to calculate amount and C.I.

In order to calculate the amount we will use the formula given below,

$\longmapsto \bf A = {P\bigg(1 + \dfrac{R}{100}\bigg)}^{n}$

Putting the given values,

$\longmapsto \rm A = {30000\bigg(1 + \dfrac{8}{100}\bigg)}^{2}$

Adding the numbers which are in brackets,

$\longmapsto \rm A = {30000\bigg( \dfrac{108}{100}\bigg)}^{2}$

Squaring the fraction,

$\longmapsto \rm A = {30000 \times \dfrac{729}{625} }$

Multiplying the fraction with the number,

$\longmapsto \rm A = { \dfrac{30000 \times 729}{625} }$

$\longmapsto \rm A = 48 \times 729$

$\longmapsto \rm A = 34992$

∴ Amount is 34992.

$\rule{200}2$

Now, We need to calculate C.I. In order to calculate C.I, We need to subtract Principal from amount.

The formula is given by –

$\longmapsto \bf C.I = A - P$

Putting the values,

$\longmapsto \rm C.I = 34992 - 30000$

Performing subtraction.

$\longmapsto \rm C.I = 4992$

∴ The compound interest is 4992.

Answer 2

Question :

Using formula calculate the amount and C.I. on rs 30000 for 2 years at 8 percent p.a. compounded annually

To Find :

The amount and Compound Interest

FormuLa Used :

$\mapsto \underline{ \boxed{{\sf \small A = P(1 + \frac{r}{100}) ^{n} }}}$

Here,

• A → Amount
• P → Principal
• r → rate of interest
• n → time

$\mapsto \underline {\boxed{ \sf \small C.I. = A - P}}$

Here,

• C.I. → Compound Interest
• A → Amount
• P → Principal

GivEn Data :

• Principal → ₹ 30000

• n → 2 years

• r → 8 % p.a. compounded annually

SoLution :

First we need to get the amount and then get the compound Interest by subtracting principal from amount

Using the first formula :

$\sf \small \leadsto A = P(1+ \frac{r}{100} )^{n}$

By putting the values we get

$\sf\small\leadsto A = 30000 {(1 + \frac{8}{100}) }^{2}$

$\sf\small\leadsto A = 30000 {(1 + \frac{2}{25} )}^{2}$

$\sf\small\leadsto A = 30000 {( \frac{25 + 2}{25} )}^{2}$

$\sf\small\leadsto A = 30000 {( \frac{27}{25}) }^{2}$

$\sf\small\leadsto A = 30000 \times \frac{729}{625}$

$\sf\small\leadsto A = \cancel{ 30000 } \times \frac{729}{ \cancel{625}}$

$\sf\small\leadsto A = 48 \times 729$

$\sf\small\leadsto A = 34992$

So the amount is ₹ 34992

Now to find the Compound Interest

$\sf\small\looparrowright C.I. = A - P$

$\sf\small\looparrowright C.I. = 34992 - 30000$

$\sf\small\looparrowright C.I. = 4992$

Hence, the Compound Interest is ₹ 4992