using identities x-y=-6 xy=4 find the value of x^3-y^3
Answers
Answered by
0
Answer:
answer is 144
Step-by-step explanation:
-6^3+3.4.-6
= 144
Answered by
2
Answer:
x^3-y^3=(x-y)(x^2+y^2+xy)
Step-by-step explanation:
x^3-y^3=(-6)[(-6-y^2)+(-6-x^2)+4]
=-6[-6-y^2-6-x^2+4]
=-6[-8-(y^2+x^2)]=48[x^2+y^2}
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