Math, asked by senthilmurugan27, 10 months ago

using identities x-y=-6 xy=4 find the value of x^3-y^3​

Answers

Answered by phytoufik
0

Answer:

answer is 144

Step-by-step explanation:

-6^3+3.4.-6

= 144

Answered by rabailzafar1998
2

Answer:

x^3-y^3=(x-y)(x^2+y^2+xy)

Step-by-step explanation:

x^3-y^3=(-6)[(-6-y^2)+(-6-x^2)+4]

=-6[-6-y^2-6-x^2+4]

=-6[-8-(y^2+x^2)]=48[x^2+y^2}

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