using identity solve (1001)3
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Answered by
11
(1001)3
(1000+1)X3
Since, (a+b)3 = a3+b3+3ab(a+b)
(1000)3+(1)3+3X1000X1(1000+1)
1000000000+1+3000X1001
1000000000+1+3003000
1003003001
ANS. 1003003001
(1000+1)X3
Since, (a+b)3 = a3+b3+3ab(a+b)
(1000)3+(1)3+3X1000X1(1000+1)
1000000000+1+3000X1001
1000000000+1+3003000
1003003001
ANS. 1003003001
Kafila:
thanks
Answered by
5
(1001)^3
= ( 1000 + 1)^3
[ ( a +b) ^3 = a^3 + b^3 + 3ab(a+b)]
= (1000)^3 + (1)^2 + 3(1000) (1)( 1000 + 1)
= 1000000000+ 1 + (3000 × 1001)
= 1000000000 + 1 + 3003000
= 1003003001
= ( 1000 + 1)^3
[ ( a +b) ^3 = a^3 + b^3 + 3ab(a+b)]
= (1000)^3 + (1)^2 + 3(1000) (1)( 1000 + 1)
= 1000000000+ 1 + (3000 × 1001)
= 1000000000 + 1 + 3003000
= 1003003001
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