Using prismoidal method, what is the volume (cubic metre) of earthwork required for 10 m deep pit, if the top and bottom dimensions are 4 m x 8 m and 8 m x 16 m respectively?
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Answered by
37
Prismoidal formulae :
V = h/6 ( A₁ + 4Am + A₂)
V= volume A₁= area of top A₂ = area of bottom Am = area of halfway the plane.
A₁ = 4 × 8 = 32m² , A₂ = 8 × 16 = 128m² , Am = {( 4+8)/2 × (8+16)/2} ×4 =288m²
h / 6= 10/6= 1.6667
Substituting in the formula :
1.667 × { 32 + 288 + 128} = 1.6667 × 448 = 746.68m³
Volume = 746.68m³
V = h/6 ( A₁ + 4Am + A₂)
V= volume A₁= area of top A₂ = area of bottom Am = area of halfway the plane.
A₁ = 4 × 8 = 32m² , A₂ = 8 × 16 = 128m² , Am = {( 4+8)/2 × (8+16)/2} ×4 =288m²
h / 6= 10/6= 1.6667
Substituting in the formula :
1.667 × { 32 + 288 + 128} = 1.6667 × 448 = 746.68m³
Volume = 746.68m³
Answered by
1
Answer:
746.67 m3
Step-by-step explanation:
D(A1+4Am+A2)/6
A1= 32
A2= 128
Am= (4+8)/2 * (16+8)/2= 72
Solve it = 746.67
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