using remainder theorem find the value of K, 2x^3-x^2-kx+10 by x+2 the remainder is 6
Answers
Answered by
0
p(x)=2x^3-X^2-kx+10
g(x)=x+2
q(x)=2x^2-5x+(10-k)
r(x)=-10-2k
6=-10-2k
=-2k=6+10
=k=16\-2
=-8
g(x)=x+2
q(x)=2x^2-5x+(10-k)
r(x)=-10-2k
6=-10-2k
=-2k=6+10
=k=16\-2
=-8
Similar questions
Social Sciences,
7 months ago
English,
7 months ago
English,
7 months ago
Hindi,
1 year ago
Science,
1 year ago