Math, asked by barnalin, 1 year ago

using remainder theorem find the value of K, 2x^3-x^2-kx+10 by x+2 the remainder is 6

Answers

Answered by sumasuma38athulya
0
p(x)=2x^3-X^2-kx+10
g(x)=x+2
q(x)=2x^2-5x+(10-k)
r(x)=-10-2k
   6=-10-2k
     =-2k=6+10
     =k=16\-2
     =-8
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