Using section formula,find the value of k for which the points with coordinates (3,2),(4,k) and (5,3) are collinear
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Using section formula,
1/2{X^1(y^2-y^3)+x^2(y^3-y^1)+x^3(y^1-y^2)}=0
=0
1/2{X^1(y^2-y^3)+x^2(y^3-y^1)+x^3(y^1-y^2)}=0
=0
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hey the answer for this is 5
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