using the identity evaluate 71 square
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Answered by
3
Explanation:
(7+1)^2
= 70^2+2×70×1+1
= 4900+140+1
= 5041
ur answer......:)
Answered by
6
An identity is true only for certain values of its variables. An equation is not an identity
The following are the identities
(a+b)sq. =a sq. +2ab+b sq.
(a-b) sq. =a sq. - 2ab- b sq.
(a-b) (a+b) = a sq. - b sq.
Another useful identity is
(x+a) (x+b) =x sq. + (a+b) x + ab
if the given expression is the difference of two squares we use the formula
a sq. - b sq. = (a+b) (a-b)
The above four identities are useful in carrying out squares and products of algebaric expressions. They also allow easy alternative methods to calculate products of no. and so on.
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