Using the point-slope formula, what is the equation of the line that passes through the points (1, 5) and (0, 0)?
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slope of line(m) = difference in ordinate /difference in abcissa in same direction
m=(y2 -y1)/(x2 -x1)
=(0 -5 )/( 0 - 1)
=-5/-1 = 5
m = 5
equation of line ,
y- y1 = m(x - x1)
y -0 =5( x - 0 )
y = 5x (answer )
m=(y2 -y1)/(x2 -x1)
=(0 -5 )/( 0 - 1)
=-5/-1 = 5
m = 5
equation of line ,
y- y1 = m(x - x1)
y -0 =5( x - 0 )
y = 5x (answer )
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