using the quadratic formula, solve the equation:p²x²-(p²-q²)x-q²=0
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Answer:
x = - q2/p2, x = 1.
Step-by-step explanation:
p2x2 - p2x +q2x -q2 = 0
p2x(x-1) + q2(x-1) = 0
(p2x+q2)(x-1) = 0
Therefore,
x= - q2/p2, x = 1
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