Question

using velocity -time graph , drive v=u + at and s= ut + 1/2 at​

Answer 1

hi

if this answer is correct

mark it as a brainliest question

Answer 2

Answer:

$\tan = slope = \frac{v - u}{t} \\ indirectly \: slope = a \\ a = \frac{v - u}{t} \\ v = u + at \\ now \: s = distance = area \: of \: the \: trapezium \: formed \\ s = \frac{1}{2} (sum \: of \: parallel \: sides)height \\ s = \frac{1}{2} (u + )t = \frac{1}{2} (u + u + at)t = \frac{1}{2}(2ut + a {t}^{2}) = ut + \frac{1}{2} a {t}^{2} \\ s = ut + \frac{1}{2} a {t}^{2}$