v=8_2t then it's initial velocity and acceleration?
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v=8-2t
initial velocity means velocity at t=0
put t=0 in equation
v=8-2 x 0=8m/sec
now again
v=8-2t
differentiate w.r.t time
dv/dt=-2 m/s^2
hence acceleration is -2m/sec^2
initial velocity means velocity at t=0
put t=0 in equation
v=8-2 x 0=8m/sec
now again
v=8-2t
differentiate w.r.t time
dv/dt=-2 m/s^2
hence acceleration is -2m/sec^2
abhi178:
are you understand
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