Question

Value of ( tan1° tan2° tan3°.........tan89° ) is :​

Answer 1

Answer:

Find the value of tan1.tan2.tan3.......................tan89.

tan 1 . tan 2 . tan 3 … tan (90 – 3 ) . tan ( 90 – 2 ) . tan ( 90 – 1)

tan 1 . tan 2 . tan 3 … cot 3 . cot 2 . cot 1

tan 1 . cot 1 . tan 2 . cot 2 . tan 3 . cot 3 … tan 89 . cot 89

We know that tanA.cotA=1

1 x 1 x 1 x 1 x … x 1

As 1ⁿ = 1