Question

Value of tan²30+2cot²60

Answer 1

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$we \: know \\ \tan(30) = \frac{1}{ \sqrt{3} } \\ \cot(60) = \frac{1}{ \sqrt{3} } \\ so \\ {tan}^{2} 30 + 2 {cot}^{2} </strong><strong>6</strong><strong>0</strong><strong>= { \frac{1}{ \sqrt{3} } }^{2} + { \frac{1}{ \sqrt{3} } }^{2} \\ = > \frac{1}{3} + \frac{1}{3} \\ = > \frac{2}{3}$

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