Question

vapour pressure of an ideal solution is given by P=195xa+260. Find P°a and P°b.

Answer 1

Answer:

P°a=455

P°b=260

Explanation:

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Answer 2

Given : Vapor pressure of an Ideal solution is given by, $P=195x_A+260$

To find : the values of $P_A^{\circ}$ and $P_B^{\circ}$

solution : Vapor pressure of an ideal gas is given by, $P=(P_A^{\circ}-P_B^{\circ})x_A+P_B^{\circ}$

on comparing we get,

$P_A^{\circ}-P_B^{\circ}=195$.......(1)

$P_B^{\circ}=260$ ........(2)

putting equation (2) in equation (1) we get,

$P_A^{\circ}-260=195$

⇒$P_A^{\circ}$ = 195 + 260 = 455

Therefore the values of $P_A^{\circ}$ and $P_B^{\circ}$ are 455 and 260 respectively.