Question

Variable x in a C Program is declared as int x[100]. Assume that each value of the array occupies one memory location, and the address of the starting memory is 2030, (a) what will be address of the last memory location? (b) What will be the address of x[15]?​

Answer 1

Answer:

a)2129 b) 2045

Explanation:

Since the memory is starting at 2030 and each array entry is taking 1 memory location

the first entry will i.e x[0](since array indexing starts at 0 not 1) will be at 2030, the next x[1] will be at 2031 and so on

this can be summarised as follows

x[0] at 2030 +0 = 2030

x[1] at 2030 + 1 = 2031

x[15] at 2030 + 15 = 2045

and the last element which is x[99] at 2030 +99 = 2129