variation of a velocity of a particle moving along a straight line is shown in the figure given below the distance travelled by a particle in 5 second is
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Answered by
372
The distance covered is the area under the graph.
Area under the graph is a trapezium.
Therefore:
Area=(a+b) /2 × h
a=1 , b=5 , h=20
5+1=6
6/2=3
3×20=60m
The distance is thus 60 M.
Area under the graph is a trapezium.
Therefore:
Area=(a+b) /2 × h
a=1 , b=5 , h=20
5+1=6
6/2=3
3×20=60m
The distance is thus 60 M.
Answered by
150
the only thing that you need to mind is the conceptual formula of straight line object
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