Math, asked by pilas3143, 1 year ago

Varun purchase two TV sets for Rs 30000 he sold one for loss of 15 %and other at gain of 19 % the selling price in both cases of the tv

Answers

Answered by mysticd
20

Answer:

 \red {selling \: price\: of \: first \:T.V }\green {=Rs\:25500}

 \red {selling \: price\: of \: second \:T.V }\green {=Rs\:35700}

Step-by-step explanation:

i ) Cost Price of first T.V = Rs 30000,

Loss (l) = 15% ,

 \boxed { \pink { selling\:price = c.p\left( \frac{100-l}{100}\right) }}

 = 30000\left( 100-15}{100}\right)\\=30000\times {85}{100}\\= Rs\:25500

ii ) Cost Price of Second T.V = Rs 30000,

Gain (g) = 19% ,

 \boxed { \pink { selling\:price = c.p\left( \frac{100+g}{100}\right) }}

 = 30000\left( 100+19}{100}\right)\\=30000\times {119}{100}\\= Rs\:35700

Therefore.,

 \red {selling \: price\: of \: first \:T.V }\green {=Rs\:25500}

 \red {selling \: price\: of \: second \:T.V }\green {=Rs\:35700}

•••♪

Answered by shailashkothari
1

Answer:

sellingpriceoffirstT.V=Rs25500

\red {selling \: price\: of \: second \:T.V }\green {=Rs\:35700}sellingpriceofsecondT.V=Rs35700

Step-by-step explanation:

i ) Cost Price of first T.V = Rs 30000,

Loss (l) = 15% ,

\boxed { \pink { selling\:price = c.p\left( \frac{100-l}{100}\right) }}

sellingprice=c.p(

100

100−l

)

\begin{gathered} = 30000\left( 100-15}{100}\right)\\=30000\times {85}{100}\\= Rs\:25500\end{gathered}

ii ) Cost Price of Second T.V = Rs 30000,

Gain (g) = 19% ,

\boxed { \pink { selling\:price = c.p\left( \frac{100+g}{100}\right) }}

sellingprice=c.p(

100

100+g

)

\begin{gathered} = 30000\left( 100+19}{100}\right)\\=30000\times {119}{100}\\= Rs\:35700\end{gathered}

Therefore.,

\red {selling \: price\: of \: first \:T.V }\green {=Rs\:25500}sellingpriceoffirstT.V=Rs25500

\red {selling \: price\: of \: second \:T.V }\green {=Rs\:35700}sellingpriceofsecondT.V=Rs35700

•••♪

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