Question

Velocity and Acceleration of a particle are V=(2i-4j)m/s and A=(-2i+4j)m/s^2
. Which type of Motion Is this??

Answer 1

Answer:

Explanation:

The velocity is,

$\vec{v} = 2\hat{i} - 4 \hat{j}$

The acceleration is,

$\vec{a} = -2 \hat{i} + 4\hat{j}$

Clearly, we can observe that,

$\vec{a} = - \vec{v}$

Therefore, the acceleration is in the negative direction of the velocity. This is evident when the change in velocity is negative. Meaning, the final velocity is of lesser magnitude than the initial velocity, and hence the acceleration is in negative direction.

From this you can deduce the type of the motion.

Answer 2

Answer:

Explanation:

Motion is one dimensional