Physics, asked by RADAL999, 9 months ago

Velocity is determined by measuring distance and time. If the % error in measuring distance is 2% and the % error in measuring time is 1%, what is the maximum % error in measuring velocity?

Answers

Answered by nirman95
0

Given:

Velocity is determined by measuring distance and time. The % error in measuring distance is 2% and the % error in measuring time is 1%.

To find:

Maximum % error in measuring velocity.

Calculation:

Velocity is calculated from the ratio of distance and time. Now , if there is a small error (<6%) in measurement of distance and time then the maximum error in velocity can be written as:

 \sf{ \therefore \: \dfrac{\Delta v}{v} \% =  \dfrac{\Delta d}{d} \% +  \dfrac{\Delta t}{t} \%}

 \sf{  =  &gt;  \: \dfrac{\Delta v}{v} \% =  2 \% +  1 \%}

 \sf{  =  &gt;  \: \dfrac{\Delta v}{v} \% =  3 \%}

So, the maximum relative error in measurement of Velocity will be 3%.

Important things to note:

  • This process is applicable only when the individual errors is less than 6%.

  • The errors can only be added.
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