Velocity vector of a flow field is given as V=(2xy)i – (x2z) j . The vorticity vector at (1, 1, 1) is
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2 unit in downward direction I. e.., opposite to +Y direction
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The velocity vector at (1,1,1) is 2i - 2j.
- The velocity vector of a flow field is given as V = (2xy)i - (x2z)j.
- To calculate the value of the vector at (1,1,1), put x = 1, y = 1 and z = 1 in the equation: V=(2xy)i – (x2z)j
- This gives the answer as V (1,1,1) = 2i - 2j.
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