verify
A={1}
B={2,5}
C={2}
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A={1}
B={2,5}
C={2}
A-(A-B)=NULL SET
A-B=[1}
A (INTERSECTION ) B=NULL SET
BOTH LHS =RHS
HENCE PROVED
A-(A-B)=A (INTERSECTION ) B
B(union)C={2,5}
A(Intersection )(B(union) C)=NULL SET
A(Intersection )B= NULL SET
A(Intersection )C=NULL SET
(A(Intersection )B)(UNION)(A(Intersection )C)=NULL SET
HENCE LHS = RHS
A(Intersection )(B(union) C )=(A(Intersection )B)(UNION)(A(Intersection )C)
B={2,5}
C={2}
A-(A-B)=NULL SET
A-B=[1}
A (INTERSECTION ) B=NULL SET
BOTH LHS =RHS
HENCE PROVED
A-(A-B)=A (INTERSECTION ) B
B(union)C={2,5}
A(Intersection )(B(union) C)=NULL SET
A(Intersection )B= NULL SET
A(Intersection )C=NULL SET
(A(Intersection )B)(UNION)(A(Intersection )C)=NULL SET
HENCE LHS = RHS
A(Intersection )(B(union) C )=(A(Intersection )B)(UNION)(A(Intersection )C)
dhiman1888pai89u:
thanks
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