Question

verify÷(a+b)+c=a+(b+c) by taking a=-2; b=-2/3; c=-3/4

Answer 1

It Is Clear By Seeing But I Will Verify
Given That a=-2,b=-2/3 And c=-3/4
LHS:-
(a+b)+c=(-2-2/3)-3/4
=
$\frac{ - 24 - 8 - 9}{12}$
$\frac{ - 41}{12}$
And Then
RHS:-
a+(b+c)=-2-(2/3-3/4)

Answer 2

Answer:

Step-by-step explanation:

Disclaimer:

Verify $(a+b)+c=a+(b+c)$ by taking $a=-2; b=-2/3; c=-3/4$ .

Concept:

Basic mathematical formula will be used to solve this question.

Given:

The value of $a$ is $-2$ , $b$ is $\frac{-2}{3}$ and the value of $c$ is $\frac{-3}{4}$ . The equation which we need to verify is $(a+b)+c=a+(b+c)$

To Find:

We have to verify the above equation.

Solution:

The value of $a$ is $-2$ .

The value of $b$ is $\frac{-2}{3}$

The value of $c$ is $\frac{-3}{4}$

First we need to get the value of L.H.S

Substitute the value in the L.H.S

Then we can write $(a+b)+c=-2+(\frac{-2}{3})+(\frac{-3}{4})$

The equation will be $-2+(\frac{-2}{3})+(\frac{-3}{4})=-2-(\frac{2}{3})-(\frac{3}{4})$

The value of L.H.S is $\frac{-41}{12}$ .

The R.H.S is $a+(b+c)$ .

Substitute the value in the R.H.S .

Therefore $a+(b+c)=-2+(\frac{-2}{3}+\frac{-3}{4})$

The value of R.H.S is $\frac{-41}{12}$ .

So L.H.S=R.H.S

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