Verify that -2,-2/3,2 are the zeroes of the polynomial p(x) =3x^3+2x^2-12-8, and then verify the relationship between the zeroes and the coefficients.
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Step-by-step explanation:
3x³+2x²-12x-8
p(x)=-2
3(-2)³+2(-2)²-12(-2)-8
3(-8)+2(4)+24-8
-24+8+24-8
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p(x)=-2/3
3(-2/3)³+2(-2/3)²-12(-2/3)-8
3(-8/27)+2(4/9)+24/3-8
-24/27+8/9+8-8
-8/9+8/9+0
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p(x)=2
3(2)³+2(2)²-12(2)-8
3(8)+2(4)-24-8
24+8-24-8
0
hope this helps you
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