Question

verify that . x³+y³+z³-3xyz=½(x+y+z)[(x-y)²+(y-z)²+(z-x)²].​

Answer 1

Answer:

x-y2=x2-2xy+y2

y-z2=y2-2yz+z2

z-x2=z2-2zx+x2

1/2=2/2cancelled(common factor)

Step-by-step explanation:

ans=x3+y3+z3-3xyz=ans is up....plse follow me

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